<PRE><B>Question 236571</B>
(79/v)+2/(v-5)=2

Multiply out gives

(79v-395+2v)/v^2-5v = 2

81v-395 = 2v^2-10V

-395 = 2v^2-91v

divide each side by 2

-395/2 = v^2-91v/2

Complete the square

-395/2 = (v-91/4)^2 - (91/4)^2

(-395/2 + (91/4)^2)^1/2 = v - 91/4

v = 17.89 + 91/4 = 40.64

OR

v = -17.89 + 91/4 = 4.86

since you can not have a negative speed (4.86 - 5) then we can ignore the second solution for v.

so the speed on the first part of the trip was 40.64 mph and 35.64mph on the second part.</PRE>