Question 236472


{{{(t^2+t-6)/(t^2-7t+10)}}} Start with the given expression.



{{{((t+3)(t-2))/(t^2-7t+10)}}} Factor {{{t^2+t-6}}} to get {{{(t+3)(t-2)}}}.



{{{((t+3)(t-2))/((t-2)*(t-5))}}} Factor {{{t^2-7t+10}}} to get {{{(t-2)(t-5)}}}.



{{{((t+3)highlight((t-2)))/(highlight((t-2))(t-5))}}} Highlight the common terms. 



{{{((t+3)cross((t-2)))/(cross((t-2))(t-5))}}} Cancel out the common terms. 



{{{(t+3)/(t-5)}}} Simplify. 



So {{{(t^2+t-6)/(t^2-7t+10)}}} simplifies to {{{(t+3)/(t-5)}}}.



In other words, {{{(t^2+t-6)/(t^2-7t+10)=(t+3)/(t-5)}}}