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You would have to choose 1 boy out of 5 boys for the first team, then for each one of those choices, 1 boy out of 4 boys for the second team, then 1 girl out of 11 girls for the first team and 1 girl out of 10 girls for the second team.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(5\cr1\right)\cdot\left(4\cr1\right)\cdot\left(11\cr\,1\right)\cdot\left(10\cr\,1\right)]


Where


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(n\cr r\right)\ =\ \frac{n!}{r!(n-r)!]


You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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