Question 235040
For this problem:

{{{(a^2-5a+6)/(a-3)}}}/{{{(a-2)}}}
You can't divide by the second fraction, so you would multiply the reciprocal like so:

{{{(a^2-5a+6)/(a-3)}}}x{{{1/(a-2)}}}

Now, when you simplify the numerator on the first fraction, you will FOIL backwards:

{{{(a-2)(a-3)/(a-3)}}}x{{{1/(a-2)}}}

Next, you can cross out like terms in the fractions:

{{{(a-2)*cross(a-3)/cross(a-3)}}}{{{1/(a-2)}}}

Now, you when you multiply across:

{{{(a-2)/(a-2)}}}
You can simplify to equal 1.