Question 235032
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Let's look at this problem in more general terms.  Let's say we have a cube that measures *[tex \Large x] on each edge.  Then the volume of that cube would be *[tex \Large x^3].  Let's double the size of each edge, so now we have *[tex \Large 2x] on each edge and the volume must be *[tex \Large (2x)^3\ =\ 8x^3].  That is 8 times the size of the original cube.  So now we know that if you double the length of each edge of any cube, you end up with a cube that is 8 times greater in volume than the original cube.

John
*[tex \LARGE e^{i\pi} + 1 = 0]
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