Question 232563
First, I recommend changing everything to cents.

Dimes is listed on both sides of the problem, this is what you will focus on then.
You want to show all coins listed in the problem:

x - will represent dimes.

10(x) + 5(x+2) + 25(x-5), notice the three coins and how they follow the problem.

10x +   5x+10  + 25x-125 = 325

so you get 40x + 10 - 125 = 325

add 115 to each side to get 40x alone 

40x + 115 - 115 = 325 + 115 

40x = 440

divide each side by 40 to get x alone

x =11, the 11 is how many dimes you have. 11(10) = 110

Two more nickels than dimes, 11 + 2 = 13, 13(5)=65

five more dimes than quarters so 11 - 5 = 6,  6(25)= 150

check: 110 + 65 + 150 = 325