Question 229172
<font face="Garamond" size="+2">


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 7x^2\ +\ 4x\ =\ 2]


First put your equation into standard form,


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 7x^2\ +\ 4x\ -\ 2\ =\ 0]


Now you can see that *[tex \Large a = 7], *[tex \Large b = 4], and *[tex \Large c = -2].


Plug it into the quadratic formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-b \pm sqrt{b^2 - 4ac}}{2a} ]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-(4) \pm sqrt{(4)^2 - 4(7)(-2)}}{2(7)} ]


The only thing left to do is the arithmetic.  I'll leave that in your capable hands.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>