Question 228956
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If the angle has been bisected, the measure of one part of the bisection has to be the same as the measure of the other half of the bisection.  However, your expressions for the measures of the two pieces make no sense.  Here's why:


Since the two pieces have to be equal:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x + 9 = 2x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = -9]


Now the total measure of the original angle must be the sum of the to parts:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x + 9 + 2x = 5x + 9]


But if *[tex \Large x = -9]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5(-9) + 9 = -45 + 9 = -36]


And a negative value for the measure of something is absurd.


On the other hand, if you had a typo and you really meant *[tex \Large 2x] and *[tex \Large 3x - 9], then everything works fine:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x - 9 = 2x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = 9]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5x - 9 = 45 - 9 = 36]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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