Question 228314
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-7,9\right)]. So this means that {{{x[1]=-7}}} and {{{y[1]=9}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(8,3\right)].  So this means that {{{x[2]=8}}} and {{{y[2]=3}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(3-9)/(8--7)}}} Plug in {{{y[2]=3}}}, {{{y[1]=9}}}, {{{x[2]=8}}}, and {{{x[1]=-7}}}



{{{m=(-6)/(8--7)}}} Subtract {{{9}}} from {{{3}}} to get {{{-6}}}



{{{m=(-6)/(15)}}} Subtract {{{-7}}} from {{{8}}} to get {{{15}}}



{{{m=-2/5}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-7,9\right)] and *[Tex \LARGE \left(8,3\right)] is {{{m=-2/5}}}