Question 227920
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-6,5\right)]. So this means that {{{x[1]=-6}}} and {{{y[1]=5}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(3,5\right)].  So this means that {{{x[2]=3}}} and {{{y[2]=5}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(5-5)/(3--6)}}} Plug in {{{y[2]=5}}}, {{{y[1]=5}}}, {{{x[2]=3}}}, and {{{x[1]=-6}}}



{{{m=(0)/(3--6)}}} Subtract {{{5}}} from {{{5}}} to get {{{0}}}



{{{m=(0)/(9)}}} Subtract {{{-6}}} from {{{3}}} to get {{{9}}}



{{{m=0}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-6,5\right)] and *[Tex \LARGE \left(3,5\right)] is {{{m=0}}}