Question 223858
Solve using elimination method


3r-2s=-15  Equation 1
2r+3s=29  Equation 2


Step 1.  Multiply Equation 1 by 3 to both sides of the equation to get Equation 1A below and Equation 2 by 2 to get Equation 2A below to eliminate the s terms when we add the following equations


9r-6s=-45  Equation 1A
4r+6s=58  Equation 2A


Step 2.  Adding Equations 1A and 2A will eliminate the s terms.


9r+4r=-45+58
13r=`13

Divide by 13 to both sides of the equation yields r=1


Step 3.  Substitute r=1 into Equation 1 to find s


3r-2s=-15 or 3-2s=-15 or -2s=-18.  Then s=9.


Step 4.  With r=1 and s=9, check Equation 2 if true  2r+3s=29 or 2*1+3*9=29 which is a true statement.


Step 5.  ANSWER:  The solution is r=1 and s=9.


I hope the above steps were helpful.


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Good luck in your studies!


Respectfully,
Dr J