<PRE><B>Question 212391</B>
: Soybean meal is 60% protein, cornmeal is 8% protein.
 How many pounds of each should be mixed together in order to get 320 pound mixture that is 9% protein?
:
Let x = amt of soy meal required
It gives total mixture as 320 lb, therefore:
(320-x) = amt of corn meal
:
A typical mixture equation:
.60x + .08(320-x) = .09(320)
:
.60x + 25.6 - .08x = 28.8
:
.60x - .08x = 28.8 - 25.6
:
.52x = 3.2
x = {{{3.2/.52}}}
x = 6.154 lb of soy meal
then
320 - 6.154 = 313.846 lb of cornmeal
:
:
Check solution in the equation
.6(6.154) + .08(313.846) = .09(320)
3.6924 + 25.108 = 28.8</PRE>