Question 188
 You start with {{{(t-2)/t=2/(t+3)}}}. The first thing you would do is cross-multiply. You would have {{{(t-2)(t+3)=(2)(t)}}}. When you multiply it out you get {{{t^2+t-6= 2t}}}. Subtract 2t from both sides and you get {{{t^2-t-6=0}}}. Factor the equation to get {{{(t-3)(t+2)=0}}}. Then you see that t= 3 or t=-2. Substitute the 3 into the original proportion and you get {{{1/3 = 1/3}}}. Substitute the -2 into the proportion and you get {{{2=2}}}.