Question 211300
Remember that if {{{log(b,(x))=y}}}, then {{{b^y=x}}}



In this case, since {{{log(x,(1/8))=-3}}}, this means that {{{x^(-3)=1/8}}}



{{{x^(-3)=1/8}}} Start with the given equation.



{{{1/(x^3)=1/8}}} Rewrite {{{x^(-3)}}} as {{{1/(x^3)}}}



{{{1*8=1*x^3}}} Cross multiply



{{{8=x^3}}} Multiply



{{{x^3=8}}} Rearrange the equation



{{{x=root(3,8)}}} Take the cube root of both sides.



{{{x=2}}} Take the cube root of 8 to get 2



So the solution is {{{x=2}}}