Question 211121
I'm assuming you want to solve for y?



{{{y+4=(2/3)(x-2)}}} Start with the given equation.



{{{y+4=(2/3)x-(2/3)2}}} Distribute



{{{y+4=(2/3)x-4/3}}} Multiply



{{{y=(2/3)x-4/3-4}}} Subtract 4 from both sides.



{{{y=(2/3)x-4/3-12/3}}} Multiply the last term by {{{3/3}}}



{{{y=(2/3)x-16/3}}} Combine like terms.



So after solving for 'y', we get {{{y=(2/3)x-16/3}}}