Question 207275
Please  check  to  amke  sure  I am  doing  the  right  problem
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(a^3b^9c^3)^(1/5) / (a^(-2) bc)^(1/2)
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  multiplying to  eliminate  powers,,,ie,,,(a^b)^c=a^(bc.
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{a^(3/5) b^(9/5)c^(3/5) } / { a^(-1)b^(1/2)c^(1/2)}
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now, term  by  term,  subtract  exponents,,ie,,a^b/a^c = a^(b-c)
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a^{(3/5)-(-1)} b^{(9/5)/(1/2)} c^{(3/5)/(1/2)}
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a^(8/5) * b^(13/10) *c^(1/10)
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check:  Let  a=2,b=3,c=4,,both  answer  and  original = 14.5,,,,ok