Question 206758
Here's an example to help you out:


{{{(28x^3y^5)/(14x^2y^3)=(14*2x^3y^5)/(14x^2y^3)=(cross(14)*2x^3y^5)/(cross(14)x^2y^3)=2x^(3-2)y^(5-3)=2x^1y^2=2xy^2}}}



So {{{(28x^3y^5)/(14x^2y^3)=2xy^2}}}



Remember, when you divide variable terms, you're subtracting the exponents.



Let me know if that helps. If not, then just email me or repost.