Question 203966
If log(x+2)/log3-log(x-2)\log3=2
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Multiply thru by log(3) to get:
If log(x+2)-log(x-2) = 2log(3)
log[(x+2)/(x-2)] = log(9)

[(x+2)/(x-2)] = 9
Cross-multiply to solve for "x":
x+2 = 9x-18
8x = 20
x = 2.5
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Cheers,
Stan H.