Question 27800
To find the area inside the square not covered by the circle, you need to find the area of the square then subtract from it the area of the circle.
It is assumed, although you don't say, that the sides of the square are tangent to the circumference of the circle.

The area of the square is found by: {{{A = S^2}}} whers S is the length of one side of the square, or 9 inches.

{{{A = 9^2}}} 
{{{A = 81}}} Square inches.

The area of the circle is found by {{{a = (pi)r^2}}} and the radius, r, of the circle is equal to half the length of one side of the square, or 4.5 inches. Using 3.14 as an approximation for {{{pi}}}

{{{a = (3.14)(4.5)^2}}}
{{{a = (3.14)(20.25)}}}
{{{a = 63.585}}}square inches.

Now you will subtract the area of the circle (63.585 square inches) from the area of the square (81 square inches)

81 - 63.585 = 17.415 Rounded to the nearest tenth this is 17.4 square inches.

Answer: 17.4 square inches.