Question 195132
Hmm...45 seems like a very long distance. If you plot the points and use the grid, you'll quickly find that 45 is way too big...





Here's how you'd find the distance:



{{{d=sqrt((x[1]-x[2])^2+(y[1]-y[2])^2)}}} Start with the distance formula.



{{{d=sqrt((-2-6)^2+(1-7)^2)}}} Plug in {{{x[1]=-2}}},  {{{x[2]=6}}}, {{{y[1]=1}}}, and {{{y[2]=7}}}.



{{{d=sqrt((-8)^2+(1-7)^2)}}} Subtract {{{6}}} from {{{-2}}} to get {{{-8}}}.



{{{d=sqrt((-8)^2+(-6)^2)}}} Subtract {{{7}}} from {{{1}}} to get {{{-6}}}.



{{{d=sqrt(64+(-6)^2)}}} Square {{{-8}}} to get {{{64}}}.



{{{d=sqrt(64+36)}}} Square {{{-6}}} to get {{{36}}}.



{{{d=sqrt(100)}}} Add {{{64}}} to {{{36}}} to get {{{100}}}.



{{{d=10}}} Take the square root of {{{100}}} to get {{{10}}}.



So our answer is {{{d=10}}} 



So the distance between the two points (-2,1) and (6,7) is 10 units.