Question 194478


{{{x+5y=10}}} Start with the given equation.



{{{5y=10-x}}} Subtract {{{x}}} from both sides.



{{{5y=-x+10}}} Rearrange the terms.



{{{y=(-x+10)/5}}} Divide both sides by {{{5}}} to isolate y.



{{{y=(-1/5)x+10/5}}} Break up the fraction.



{{{y=-(1/5)x+2}}} Reduce.



So the equation {{{y=-(1/5)x+2}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-1/5}}} and the y-intercept is {{{b=2}}} 



note: the y-intercept is the point *[Tex \LARGE \left(0,2\right)]