Question 193566
You need to find the value of the discriminant of the equation.
If the discriminant > = 0, then the equation has real solutions. Otherwise only complex solutions.

Recall that 
The discriminant = {{{b^2 - 4ac}}} for equation {{{ax^2+bx +c=0}}}
So
The discriminant = 
={{{(-4)^2-4*sqrt(2)*(-7sqrt(2))}}}
={{{16+56}}}
={{{72}}} > 0
So the equation has 2 real roots