Question 191963
{{{(4/(x+3))/(1/x+3)}}} Start with the given expression.



{{{(x*cross((x+3))(4/cross((x+3))))/(cross(x)(x+3)(1/cross(x))+3x(x+3))}}} Multiply EVERY term by the inner LCD {{{x(x+3)}}} to clear out the fractions.



{{{(4x)/(x+3+3x(x+3))}}} Multiply and simplify



{{{(4x)/(x+3+3x^2+9x)}}} Distribute



{{{(4x)/(3x^2+10x+3)}}} Combine like terms.



So {{{(4/(x+3))/(1/x+3)=(4x)/(3x^2+10x+3)}}} where {{{x<>0}}}, {{{x<>-3}}}, or {{{x<>-1/3}}}