Question 189765
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Given points: (-8,0) and (0,3)


Via Point-Slope Form, {{{m=(y[2]-y[1])/(x[2]-x[1])}}}
{{{m=(3-0)/(0-(-8))=3/8}}}


Finding y-Intercept "b" via Slope-Intercept Form:


We take thru point (0,3)
{{{y=mx+b}}}
{{{3=(3/8)(0)+b}}}
{{{red(b=3)}}}, y-Intercept (0,3)


Then it follows ---> {{{highlight(red(y=(3/8)x+3))}}} or 
{{{(-3/8)x+y-3=0}}} ---> {{{highlight(red(-3x+8y-24=0))}}}, Std Form 


Thank you,
Jojo</font>