Question 188263
One coin is 2 years older than another. In 3 years, the product of their ages will be 35. Find the present ages of the coins. _______ and _______ 
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age of 1st coin = y  (number of years)
age of 2nd coin = y+2
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In 3 years:
(y+3)*(y+5) = 35
{{{y^2 + 8y + 15 = 35}}}
{{{y^2 + 8y - 20 = 0}}}
(y + 10)*(y  - 2) = 0
y = 2 years (ignore the -10)
2nd coin is 4 years old