<PRE><B>Question 183982</B>
HEY, YOU GAVE IT A SHOT!!!!!  TRY TO FOLLOW THIS:
Distance(d) equals Rate(r) times Time(t) or d=rt;  r=d/t and t=d/r

Average Speed=(Total Distance)/(Total Time)

Time required on the outward leg=L/160
Time required on the return leg=L/240

Total Distance=2L
Total Time=L/160 + L/240=3L/480 + 2L/480=5L/480=L/96, so:

Average Speed=2L/(L/96)=(2L*96)/L=192 mph--------------ans


Hope this helps----ptaylor
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