<PRE><B>Question 25671</B>
{{{ sqrt(x^2+5) = x+3}}}


Square both sides:
{{{x^2 + 5 = (x+3)^2}}}

{{{x^2 + 5 = x^2 + 6x + 9}}}


Subtract x^2 from each side:
{{{5 = 6x + 9}}}
{{{5-9 = 6x}}}
{{{-4/6= x}}}
{{{x=-2/3}}}


Check answer for extraneous roots:
{{{ sqrt(4/9+5) = -2/3 +3}}}
{{{ sqrt (4/9 +45/9 ) = -2/3+9/3}}}
{{{ sqrt (49/9) = 7/3}}}
{{{7/3=7/3}}}
It checks!!


R^2 at SCC</PRE>