Question 25353
{{{(1/25)^(-x)=125^(x-3)}}}
{{{(25)^x = 125^(x-3)}}}


Now 25 is {{{5^2}}} and 125 is {{{5^3}}}, so we have

{{{(5^2)^x = (5^3)^(x-3)}}}
{{{5^(2x) = 5^(3(x-3))}}}


so we have 5 to a power on both sides and it is an equation, so the powers must be the same number, so 2x = 3(x-3)


Hence 2x = 3x-9
--> x = 9


jon