Question 181114
Let {{{r}}} = the rate of the slower squad
Let {{{d}}} = the distance the slower squad travels in 3 hrs
given:
The rate of the faster squad is
{{{(r + (2/3))}}}
The distance the faster squad travels in 3 hrs is
{{{26 - d}}}
---------------------
For slower squad:
(1) {{{d = 3r}}}
For faster squad:
{{{26 - d = (r + (2/3))*3}}}
{{{26 - d = 3r + 2}}}
(2) {{{d = 24 - 3r}}}
Subtract (1) from (2)
(2) {{{d = 24 - 3r}}}
(1) {{{-d = -3r}}}
{{{0 = 24 - 6r}}}
{{{6r = 24}}}
{{{r = 4}}} mi/hr
The rate of the faster squad is
{{{r + (2/3) = 4.67}}}mi/hr
The faster squad's rate was 4.67 mi/hr
check answer
{{{d = 3r}}}
{{{d = 12}}} mi
{{{26 - d = (r + (2/3))*3}}}
{{{26 - 12 = (r + (2/3))*3}}}
{{{14  = 3r + 2}}}
{{{3r = 12}}}
{{{r = 4}}} mi/hr
OK