Question 180097
The force of the wind blowing on a verticle surface varies jointly as the area of the surface and the square of the velocity.
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f = kAv^2
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If a wind blowing at 50 miles per hour exerts a force of 75 pounds on a surface of 500 ft squared,
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solve for "k":
50 = k*500*75^2
k = 50/(500*75^2)
k = 0.0000178
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 how much force will a wind of 75 mph place on a surface of 10 ft squared. 

f = (0.0000178)(10)*75^2

force = 1 lb
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Cheers,
Stan H.