Question 178565
what quantity x of an 80% solution must be added to a 15% solution to produce 600mL of a 40% solution
:
let x and y be amounts of 80% and 15% solutions respectively
:
x+y=600.....eq 1
.8x+.15y=.4(600)...eq 2
:
rewrite eq 1 to x=600-y and place that value into eq 2
:
.8(600-y)+.15y=.4(600)
:
480-.8y+.15y=240
:
-.65y=-240
:
{{{y=369.23}}}ml of 15% solution
:
x=600-y{{{x=600-369.23=highlight(230.77)}}}ml of 80% solution