<PRE><B>Question 178069</B>
TWO JETS LEAVE DENVER AT 9 AM ONE FLYING EAST AT A SPEED 50km/h GREATER THAN THE OTHER,WHICH IS TRAVELING WEST.AT 11 AM THE PLANES ARE 2500 km APART .FIND THERE SPEEDS. 
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East jet DATA:
rate =  (x+50) km/h ; time = 2 hr ; distance = rt = 2(x+50) km
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West jet DATA:
rate = x km/h ; time = 2 hr ; distanc e= 2x km
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Equation:
distance + distance = 2500
2(x+50) + 2x = 2500
4x = 2400
x = 600 km/h (speed of the west jet)
x+50 = 650 km/h (speed of the east jet)
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Cheers,
Stan H.</PRE>