Question 24719
See if you can find a pattern in the sum of the digits for:
(3+1)^2 = 3^2+3(3)+1
(33+1)^2= 33^2+2(33)+1
(333+1)^2= 333^2+2(33)+1
etc.
Your number is (3333333333+1)^2
I got an answer of sum of digits is 61 but
I may have made a mistake along the line.

Cheers,

Stan H.