Question 176170
First, let's declare some variables:
x: cost of 1m radiator
y: cost of 1.5m radiator
Then, the first sentence tell us that
{{{4x+3y=159}}} and the second tells us
{{{5x+2y=134}}}
Let's use the addition method to solve.  I will multiply the first equation by 5, and the second equation by -4:
{{{20x+15y=795}}}
{{{-20x-8y=-536}}}
Now we add the two together:
{{{7y=259}}}
{{{y=37}}}
So the 1.5m radiator costs £37.  Now, to find the cost of the 1m radiator, we substitute in this y value to either of the equations.  I will use the first one for simplicity:
{{{4x+3(37)=159}}}
{{{4x+111=159}}}
{{{4x=48}}}
{{{x=12}}}
So the 1m radiator costs £12.