Question 175820
First find the fraction of the class that got B's
and then convert the fraction to %
The fraction that got B's is
(number of B's)/(total number that were tested)
{{{42/(10 + 42 + 15 + 8 + 2) = 42/77}}}
{{{42/77 = 6/11}}}
{{{6/11 = .5454}}}
Now I want to convert this to percent
I know that {{{.5 = 50}}}%
This is a little more that {{{.5}}}, or 54.5%
approximately