Question 172924
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Let's see;
{{{A[S]=s^2=(5ft)^2=25ft^2}}}
{{{A[C]=(pi)d^2/4=(pi)(6ft)^2/4=28.27ft^2}}}
Then,
{{{A[C]-A[S]=28.27-25=highlight(3.27ft^2)}}}, This much smaller  the Area of Square than the Circle.
Or, {{{(3.27/28.27)100}}}=11.567% smaller than the Area of Circle
Thank you,
Jojo</pre>