Question 167951
{{{((x^3 - 1))/((1 - x))}}}
:
Recognize the numerator can be factored as the "difference of cubes"
{{{((x-1)(x^2+x+1))/((1 - x))}}}
:
Factor out -1 in the denominator and you have;
{{{((x-1)(x^2+x+1))/(-1(x-1))}}}
:
Cancel out the (x-1)'s and you have:
{{{((x^2+x+1))/(-1)}}}
:
Which is:
{{{-(x^2+x+1)}}}
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