Question 167702
{{{f(x)=0.004x^3-0.2x^2+5.2x+6}}} Start with the given function.



{{{f(50)=0.004(50)^3-0.2(50)^2+5.2(50)+6}}} Plug in {{{x=50}}}.



{{{f(50)=0.004(125000)-0.2(50)^2+5.2(50)+6}}} Cube {{{50}}} to get {{{125000}}}.



{{{f(50)=0.004(125000)-0.2(2500)+5.2(50)+6}}} Square {{{50}}} to get {{{2500}}}.



{{{f(50)=500-500+260+6}}} Multiply



{{{f(50)=266}}} Combine like terms.



So at {{{x=50}}}, the height of the track is 266 units (replace this with the given units ie feet or meters)