Question 23442
{{{-2(2c-4)=(1/3)*(-12c+24)}}}

The first step for me is to clear the fraction, by multiplying both sides by the denominator which is 3.

{{{3*(-2)*(2c-4)=3*(1/3)*(-12c+24)}}}

{{{-6*(2c-4)=(-12c+24)}}}

{{{-12c + 24 = -12c + 24 }}}


This is an IDENTITY, so the solution is all real values of c.


R^2 at SCC