Question 21296
{{{A= pi* r^2}}}


d= 16 m (all the way across the circle!), so r= 8 m.  

{{{ A = pi * 8^2}}}

{{{ A = 64* pi }}} square meters
Using {{{pi = 3.14}}}, A = 200.96 approximately, which rounds of to nearest tenth to 201.0


Using the calculator value for {{{pi}}}, 
A = 201.06, which also rounds off to 201.0


Final answer:  201.0


R^2 at SCC