Question 22132
To solve two equations and two unknowns by graphing (which is NOT the best way to solve a system of equations like this!), you have to draw the graphs first.  You can either solve for y and graph by the slope-intercept method, or you can just find the two intercepts for each line, and graph those.  I prefer the second method, finding the two intercepts, since these equations are written in standard form.


3x+4y = 2
Let x =0, then 4y = 2, so y = 1/2
Let y= 0, then 3x = 2, so x = 2/3


x-y=1
Let x=0, then -y = 1, so y = -1
Let y=0, then x= 1.  

Graph these two lines, and see where the graphs intersect.  You might be able to identify the point where they cross, and this will be the solution point.

{{{graph(300,300, -5,5,-5,5, (-3x+2)/4, x-1) }}}

You can see that they cross at an uneven point, very close to x= 1 and y= 0.  If you want to find the point where they cross, you should probably solve the system by the elimination method, which give you a EXACT values for the point of intersection.


R^2 at SCC