Question 156681
{{{x/(x^2 - 1)  + 1/(x - 1)  = 1/(x + 1)}}}


Common denominator=(x-1)(x+1)---because x^2-1 = (x-1)(x+1)


{{{x/((x-1)(x+1))  + (x+1)/((x-1)(x+1))   =  (x-1)/((x-1)(x+1))}}}


Add the numerators on the left side
{{{(2x+1)/((x-1)(x+1))=(x-1)/((x-1)(x+1))}}}


If this is true, than 2x+1=x-1


{{{2x+1=x-1}}}


Subtract x from both sides
{{{x+1=-1}}}


Subtract 1 from both sides
{{{x=-2}}}
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I hope this helped!
-Alani