Question 22945
{{{x(3x+2)=(x+2)^2}}}
{{{3x^2 + 2x = x^2 + 4x + 4}}}


Set equation equal to zero by adding {{{-x^2-4x -4}}} to each side: 
{{{2x^2-2x -4 = 0}}}


Factor the common factor of 2:
{{{2(x^2 - x - 2)=0}}}


Factor the trinomial:
{{{2(x-2)(x+1) = 0}}}


Set each factor equal to zero.  The 2 from the common factor does not give any solutions.

x-2=0, so x=2


x+1=0, so x=-1


R^2 at SCC