Question 150949
{{{sqrt(32*x^6*y^11)=sqrt(2*16*x^6*y^10*y)=sqrt(16*x^6*y^10*2*y)=4x^3*y^5*sqrt(2*y)}}}
{{{2x*sqrt(98x^4y^11)=2x*sqrt(2*49*x^4*y^10*y)=2x*sqrt(49*x^4*y^10*2*y)
=2*x*7*x^2*y^5*sqrt(2*y)=14x^3*y^5*sqrt(2*y)}}}
So
{{{sqrt(32*x^6*y^11)+2x*sqrt(98x^4y^11)=4x^3*y^5*sqrt(2*y)+14x^3*y^5*sqrt(2*y)
=18x^3*y^5*sqrt(2*y)}}}