Question 149447
With the given domain values are -1,0,1/2, and 2, we can find the corresponding range values by plugging in each value. So I'll do the first one and the third one.


# 1


Let's find the corresponding range value for {{{x=-1}}}




{{{y=8x^2-4x-5}}} Start with the given equation.



{{{y=8(-1)^2-4(-1)-5}}} Plug in {{{x=-1}}}.



{{{y=8(1)-4(-1)-5}}} Square {{{-1}}} to get {{{1}}}.



{{{y=8-4(-1)-5}}} Multiply {{{8}}} and {{{1}}} to get {{{8}}}.



{{{y=8+4-5}}} Multiply {{{-4}}} and {{{-1}}} to get {{{4}}}.



{{{y=7}}} Combine like terms.



So with the given domain value of {{{x=-1}}}, the corresponding  range value is {{{y=7}}}




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# 3


Let's find the corresponding range value for {{{x=1/2}}}


{{{y=8x^2-4x-5}}} Start with the given equation.



{{{y=8(1/2)^2-4(1/2)-5}}} Plug in {{{x=1/2}}}.



{{{y=8(1/4)-4(1/2)-5}}} Square {{{1/2}}} to get {{{1/4}}}.



{{{y=2-4(1/2)-5}}} Multiply {{{8}}} and {{{1/4}}} to get {{{2}}}.



{{{y=2-2-5}}} Multiply {{{-4}}} and {{{1/2}}} to get {{{-2}}}.



{{{y=-5}}} Combine like terms.



So with the given domain value of {{{x=1/2}}}, the corresponding  range value is {{{y=-5}}}