Question 147812
perpendicular lines, one that passes through the point (3,-4) and the other that passes through the point (7,2).
:
Choose a convenient slope and write an equation for the (3,-4) coordinates
Let m1 = 2
:
y - (-4) = 2(x - 3)
y + 4 = 2x - 6
y = 2x - 6 - 4
y = 2x - 10 is one line
:
Slope relationship of perpendicular lines: m1*m2 = -1
The slope of the second equation:
2*m2 = -1
m2 = {{{-1/2}}}; coordinates (7,2)
:
y - 2 = {{{-1/2}}}(x - 7)
y - 2 = {{{-1/2}}}x + {{{7/2}}}
y = {{{-1/2}}}x + {{{7/2}}} + {{{4/2}}}
y = {{{-1/2}}}x + {{{11/2}}} is the 2nd line
:
Graphing this we have
{{{ graph( 300, 300, -10, 12, -10, 9, 2x-10, -.5x+5.5) }}}
:
You can check the equations by substituting the given values for x and finding y