Question 147665
1/2√8-1/3√27+4√50

To fine the square root of a number, find two factors of it, one of which is a perfect square.  Perferably the highest perfect square that is a factor of the number.  So the square root of 8 would be {{{sqrt(4)*sqrt(2)}}}.  You can simplify that two {{{2sqrt(2)}}}, since the square root of four is two.  So substitute that and get {{{1/2(2sqrt(2))-1/3(sqrt(27))+4(sqrt(50))}}}. Then find the square root of 27. You should get {{{3sqrt(3)}}}.  Then get the square root of 50. You should get {{{5sqrt(2)}}}.  Then plug these in to the original equation. {{{1/2(2sqrt(2))-1/3(3sqrt(3))+4(5sqrt(2))}}}. Then multiply everything and get {{{sqrt(2)-sqrt(3)+20sqrt(2)}}}.  Combine like terms and get {{{21(sqrt(2))-sqrt(3)}}}.