Question 21975
Rewritten, your question equation is:
log[5]x +log[5]x+4=log[5]5
**NUMBER IN BRACKET IS THE BASE OF THE LOGARITHM**
I'm assuming your question is "solve for x"
Well, the first law of logarithms is:
log[a]x+log[a]y=log[a]xy
So, in your case
{{{x*y=5}}}
log[5]x(x+4)=log[5]5
log[5]x^2+4=log[5]5
{{{x^2+4 =5}}}
{{{x^2=1}}}
{{{highlight(x=1)}}}
Hope this helps!