Question 144660
let x=diagonal, so x-3.6=length and x-7.1=width


x^2=(x-3.6)^2+(x-7.1)^2 __ x^2=x^2-7.2x+12.96+x^2-14.2x+50.41


subtracting x^2 __ 0=x^2-21.4x+63.37


use quadratic formula to find x