Question 139969
Solve for x:
{{{log((7x+8)) = 2*log((x))}}} Apply the power rule to the right side.
{{{log((7x+8)) = log((x^2))}}} Now, if {{{Log[b](M) = Log[b](N)}}} then {{{M = N}}}, so...
{{{7x+8 = x^2}}} Subtract 7x+8 from both sides.
{{{x^2-7x-8 = 0}}} Factor the trinomial.
{{{x+1)(x-8) = 0}}} Apply the zero product rule:
{{{x+1 = 0}}} or {{{x-8 = 0}}}, so...
{{{x = -1}}} or {{{x = 8}}}